x^2(x-1)^2+x(x^2-1)=2(x+1)^2

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Solution for x^2(x-1)^2+x(x^2-1)=2(x+1)^2 equation: 



x^2(x-1)^2+x(x^2-1)=2(x+1)^2

We move all terms to the left:

x^2(x-1)^2+x(x^2-1)-(2(x+1)^2)=0

We multiply parentheses

x^2(x-1)^2+x^3-1x-(2(x+1)^2)=0



We calculate terms in parentheses: -(2(x+1)^2), so:

2(x+1)^2



We do not support expression: x^3

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